Question

Determine the margin of error for a 99% confidence interval to estimate the population mean when s = 40 for the sample sizes below. a) nequals12 b) nequals25 c) nequals50

a) The margin of error for a 99% confidence interval when nequals12 is _____. (Round to two decimal places as needed.)

b) The margin of error for a 99% confidence interval when nequals25 is ____. (Round to two decimal places as needed.)

c) The margin of error for a 99% confidence interval when nequals50 is ____ (Round to two decimal places as needed.)

Answer #1

Margin of error when population standard deviation () is unknown and sample size(n) is small

Margin of error for large sample

a) n=12, s=40

t value at 99% confidence interval with 11 (n-1=12-1) degrees of freedom= 3.1058

=35.85

b) n=25

t value at 99% confidence interval with 24 degrees of freedom= 2.7969

= 22.38

c) n=50

z value for 99% confidence interval = 2.5758

= 14.57

Determine the margin of error for
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37
for the sample sizes below.
a)
nequals=15
b)
nequals=34
c)
nequals=46
a) The margin of error for
a
95%
confidence interval when
nequals=15
is
nothing.
(Round to two decimal places as needed.)
b) The margin of error for
a
95%
confidence interval when
nequals=34
is
nothing.
(Round to two decimal places as needed.)
c) The margin of error for
a
95%...

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a)
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b)
n=40
c)
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(Round to two decimal places as needed.)

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b)
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c)
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(Round to two decimal places as needed.)
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