A committee has six members. There are three members that currently serve as the board's chairman comma vice chairman comma and treasurer . Each member is equally likely to serve in any of the positions. Three members are randomly selected and assigned to be the new chairman comma vice chairman comma and treasurer . What is the probability of randomly selecting the three members who currently hold the positions of chairman comma vice chairman comma and treasurer and reassigning them to their current positions?
The probability is ?
Solution: What is the probability of randomly selecting the three members who currently hold the positions of chairman, vice chairman, and treasurer and reassigning them to their current positions?
Answer: To find the given probability, we first need to find the number of ways in which three positions can be filled.
Since we need to select three members from a committee of six member. Therefore the possible number of ways is:
Now there is only 1 of these ways will have their previous members in their former positions.
So, the probability of randomly selecting the three members who currently hold the positions of chairman, vice chairman, and treasurer and reassigning them to their current positions is
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