. A sample of 25 items yields X(bar) = 60 grams and s = 9 grams. Assuming a normal parent distribution, construct a 99 percent confidence interval for the population mean weight.
Given, = 60, s = 9, n = 25
Since population standard deviation is unknown and n < 30, we use the t distribution
The tcritical (2 tail) for = 0.01, degrees of freedom = n - 1 = 25 - 1 = 24 is 1.960
The Confidence Interval is given by ME, where
The Lower Limit = 60 - 5.035 = 54.965
The Upper Limit = 60 + 5.035 = 65.035
The 99% Confidence Interval is 54.965 , 65.035
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