Refer to the accompanying data display that results from a sample of airport data speeds in Mbps. Complete parts (a) through (c) below. |
TInterval |
(13.046,22.15) x overbarxequals=17.598 Sxequals=16.01712719 nequals=50 |
a. Express the confidence interval in the format that uses the "less than" symbol. Given that the original listed data use one decimal place, round the confidence interval limits accordingly.
____Mbpsless than<muμless than<______ Mbps
(Round to two decimal places as needed.)
b. Identify the best point estimate of
muμ and the margin of error.The point estimate of μ is ____ Mbps.
(Round to two decimal places as needed.)
The margin of error is E equals=_____Mbps.
(Round to two decimal places as needed.)
c. In constructing the confidence interval estimate of muμ,why is it not necessary to confirm that the sample data appear to be from a population with a normal distribution?
A.
Because the sample standard deviation is known, the normal distribution can be used to construct the confidence interval.
B.
Because the sample is a random sample, the distribution of sample means can be treated as a normal distribution.
C.
Because the population standard deviation is known, the normal distribution can be used to construct the confidence interval.
D.
Because the sample size of 50 is greater than 30, the distribution of sample means can be treated as a normal distribution.
Click to select your answer(s).
A.
n = 50
= 17.6
s = 16
(All data rounded to one decimal place)
Confidence Interval: 13.05 < < 22.15
B.
Best Point estimate of = 17.60
Margin of Error, E = 22.147-17.60
= 4.547
~ 4.55
C.
Correct Option is D.
Because the sample size of 50 is greater than 30, the distribution of sample means can be treated as a normal distribution.
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