A sample of 21 items was taken, and 4 of the units were found to be green. What is the 98% upper confidence limit (one-sided) for the percentage of green items?
Solution :
Given that,
Point estimate = sample proportion =
= x / n = 4 / 21 = 0.1905
Z/2
= 2.054
Margin of error = E = Z
*
((
* (1 -
)) / n)
= 2.054 * (((0.1905
* 0.8095) / 21)
= 0.176
The 98% upper confidence limit (one-sided) for the percentage of green items is,
+ E = 0.1905 - 0.176 = 0.0145 = 1.45%
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