Question

The following bivariate data set contains an outlier.

x	y
76.1	1194.8
67.6	1146.3
57.4	1189.2
61.8	-4184.5
86.7	280.8
71.5	-1445.2
74.1	325.8
75.3	955.7
70.5	399.8
52.4	-1084.3
70.5	2936.8
54.2	2258.3
62.9	1020
52.5	-80
189.6	-25548.4

What is the correlation coefficient with the outlier?
r_w =

What is the correlation coefficient without the outlier?

please explain in ti-84 terms

Answer 1

Using TI 84 calculator

first, add the data sets in L1 and L2 list (STAT>EDIT>press enter)

Now, press 2nd then CATALOG then select Diagnostic on, press enter

it will show "DONE"

then press stat calc and select LinReg(ax+b)

select L1 and L2 data set

press calculate

we get r = -0.9177 (with outlier)

Again, go to L1 and L2 and remove the outlier

then

press 2nd then CATALOG then select Diagnostic on, press enter

it will show "DONE"

then press stat calc and select LinReg(ax+b)

select L1 and L2 data set

press calculate

we get r = 0.1228 (without outlier)