Question

Find out the 99 % confidence for a sample whose Mean= 40 and Standard Deviation=1.5. The sample size is=100.

** please I need the answer in the computer typing not hand writing.

Subject: Statistic

Answer #1

t critical value at 0.01 level with 99 df = 2.626

99% confidence interval for is

- t * S / sqrt(n) < < + t * S / sqrt(n)

40 - 2.626 * 1.5 / sqrt(100) < < 40 + 2.626 * 1.5 / sqrt(100)

39.6061 < < 40.3939

99% CI Is **( 39.61 , 40.39)** (Rounded to two
decimals)

Find the area between z=2 and z=-1.30. State your results in
percentage terms..
** please I need the answer in the computer typing not hand
writing.
Subject: Statistic

Mean
Sample standard deviation
Population standard deviation
Sample size
Confidence level
Confidence interval
100
20
na
25
95 %
100
20
na
25
90 %
100
40
na
25
90 %
100
40
n.a.
16
90 %
100
n.a.
40
16
90 %
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