Question

Find out the 99 % confidence for a sample whose Mean= 40 and Standard Deviation=1.5. The sample size is=100.

** please I need the answer in the computer typing not hand writing.

Subject: Statistic

Answer 1

t critical value at 0.01 level with 99 df = 2.626

99% confidence interval for is

- t * S / sqrt(n) < < + t * S / sqrt(n)

40 - 2.626 * 1.5 / sqrt(100) < < 40 + 2.626 * 1.5 / sqrt(100)

39.6061 < < 40.3939

99% CI Is ( 39.61 , 40.39) (Rounded to two decimals)