Question

# PLease make sure you know the corract answer and answer the three questions 1-Blood glucose levels...

1-Blood glucose levels were recorded for all males over the age of 40, admitted with a diagnosis of coronary artery disease (a total of 755 diagnosed cases). The lowest blood glucose level recorded was 58 and the highest, 442. Using a class interval size of 25, set the score limits for each interval........

2-- A total of 320 patients were treated at a clinic in the past year for sexually transmitted infections (STIs). Excluding 32 cases that resulted from congenital transmission or sexual abuse, construct the limits for a frequency distribution of the remaining cases (288), if the oldest patient was 88 and the youngest 12 years of age........

3-The age of all patients diagnosed with cancer during the past year (255 new cases) was recorded. The youngest patient was 3 years old and the oldest was 92. Determine the number of class intervals......

(1)

Lowest value = 58

Highest Value = 442

Class size = 25

Score limits for each interval are as follows:

58 - 83

83 - 108

108 - 133

133 - 158

158 - 183

183 - 208

208 - 233

233 - 258

258 - 283

183 - 308

308 - 333

333 - 358

358 - 383

383 - 408

408 - 433

433 - 458

(2)

Lowest value = 12

Highest value = 88

Difference = 88 - 12 = 76

So,

Number of classes = 76/8 = 9.5 = 10 (round to integer)

Class width =76/10 = 7.6

Thus,

the limits for a frequency distribution are given by:

12 - 19.6

19.6 - 27.2

27.2 - 34.8

34.8 - 42.4

42.4 - 50

50 - 57.6

57.6 - 65.2

65.2 - 72.8

72.8 - 80.4

80.4 - 88

(3)

Lowest value = 3

Highest value = 92

Sturges Formula:

K = 3.322 log N

= 3.322 X log (255)

= 3.322 X 2.4065

= 7.9945

= 8 (Round to integer)

So,

8

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