Use the normal distribution of SAT critical reading scores for which the mean is
507507
and the standard deviation is
108108.
Assume the variable x is normally distributed.
left parenthesis a right parenthesis(a) |
What percent of the SAT verbal scores are less than
650650? |
left parenthesis b right parenthesis(b) |
If 1000 SAT verbal scores are randomly selected, about how
many would you expect to be greater than
575575? |
left parenthesis a right parenthesis(a)
Approximately
1.341.34%
of the SAT verbal scores are less than
650650.
(Round to two decimal places as needed.)
left parenthesis b right parenthesis(b)
You would expect that approximately
1.321.32
SAT verbal scores would be greater than
575575.
(Round to the nearest whole number as needed.)
for normal distribution z score =(X-μ)/σx | |
here mean= μ= | 507 |
std deviation =σ= | 108.000 |
a)
probability =P(X<650)=(Z<(650-507)/108)=P(Z<1.32)=0.9073 ~ 90.73 % |
Approximately 90.73 % of the SAT verbal scores are less than 650.
2)
probability =P(X>575)=P(Z>(575-507)/108)=P(Z>0.63)=1-P(Z<0.63)=1-0.7355=0.2645 |
You would expect that approximately 1000*0.2645 ~ 265 SAT verbal scores would be greater than 575.
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