A social scientist measures the number of minutes (per day) that a small hypothetical population of college students spends online. Student Score Student Score A 31 F 86 B 95 G 55 C 99 H 86 D 92 I 99 E 83 J 74 (a) What is the range of data in this population? Correct: Your answer is correct. min (b) What is the IQR of data in this population? Correct: Your answer is correct. min (c) What is the SIQR of data in this population? Correct: Your answer is correct. min (d) What is the population variance? (e) What is the population standard deviation? (Round your answer to two decimal places.) min
By writing the scores in ascending order
31, 55, 74, 83, 86, 86, 92, 95, 99, 99
a) Range = 99 - 31 = 68
b) Median = (86 + 86)/2 = 86
Q1 = 74
Q3 = 95
IQR = Q3 - Q1 = 95 - 74 = 21
c) SIQR = 21/2 = 10.5
d) = (31 + 55 + 74 + 83 + 86 + 86 + 92 + 95 + 99 + 99)/10 = 80
= ((31 - 80)^2 + (55 - 80)^2 + (74 - 80)^2 + (83 - 80)^2 + (86 - 80)^2 + (86 - 80)^2 + (92 - 80)^2 + (95 - 80)^2 + (99 - 80)^2 + (99 - 80)^2)/10 = 423.4
= = 20.58
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