Question

In a certain lottery, an urn contains balls numbered 1 to 33. From this urn, 4 balls are chosen randomly, without replacement. For a $1 bet, a player chooses one set of four numbers. To win, all four numbers must match those chosen from the urn. The order in which the balls are selected does not matter. What is the probability of winning this lottery with one ticket?

Answer #1

The probability of winning this lottery with one ticket = Number of favorable events/ Total number of events

Since the order in which the balls are selected does not matter:

Number of favorable events = Number of permutations of winning set of 4 numbers and is given by:

Total number of events = Number of ways of selecting 4 numbers from 33 numbers and is given by:

So,

The probability of winning this lottery with one ticket = 24/40920 = 0.0005865

So,

Answer is:

**0.0005865**

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