Question

The college Physical Education Department offered an Advanced First Aid course last summer. The scores on the comprehensive final exam were normally distributed, and the z scores for some of the students are shown below. Robert, 1.18 Juan, 1.80 Susan, –2 Joel, 0.00 Jan, –0.66 Linda, 1.54 (a) Which of these students scored above the mean? (Select all that apply.) Jan Joel Juan Linda Robert Susan (b) Which of these students scored on the mean? (Select all that apply.) Jan Joel Juan Linda Robert Susan (c) Which of these students scored below the mean? (Select all that apply.) Jan Joel Juan Linda Robert Susan (d) If the mean score was μ = 160 with standard deviation σ = 18, what was the final exam score for each student? (Round your answers to the nearest whole number.) Robert Joel Jan Juan Susan Linda

Answer 1

a)

Robert Juan , Linda

b)

Joel

c)

Jan , Susan

d)

For Robert
z value =1.18
z = (x - mean)/sigma

1.18 = (x - 160)/18

x = 1.18 * 18 + 160
x = 181

For Joel

z = (x - mean)/sigma

0 = (x - 160)/18

x = 0 * 18 + 160
x = 160

For Jan

z = (x - mean)/sigma

-0.66 = (x - 160)/18

x = -0.66 * 18 + 160
x = 148

For JUan

z = (x - mean)/sigma

1.80 = (x - 160)/18

x = 1.80 * 18 + 160
x = 192

For Susan

z = (x - mean)/sigma

-2 = (x - 160)/18

x = -2 * 18 + 160
x = 124

FOr Linda

z = (x - mean)/sigma

1.54 = (x - 160)/18

x = 1.54* 18 + 160
x = 188