Given a normal distribution with
mu=103
and
sigma?=15 ,
and given you select a sample of
n=9
What is the probability that
Upper X overbarX
is less than
95 ?
= 103
= 15
n = 9
= 103
=
= 5
For sampling distribution of mean, P( < 95) = P(Z < (95 - ) / )
= P(Z < (95 - 103)/5)
= P(Z < -1.6)
= 0.0548
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