Two wine tasters rate each wine they taste on a scale of 1 to 5. From data on their ratings of a large number of wines, we obtain the following probabilities for both tasters' ratings of a randomly chosen wine.
Taster 2 | |||||
Taster 1 | 1 | 2 | 3 | 4 | 5 |
1 | 0.03 | 0.02 | 0.01 | 0.00 | 0.00 |
2 | 0.02 | 0.09 | 0.05 | 0.02 | 0.00 |
3 | 0.01 | 0.05 | 0.29 | 0.05 | 0.01 |
4 | 0.00 | 0.02 | 0.05 | 0.20 | 0.01 |
5 | 0.00 | 0.00 | 0.01 | 0.01 | 0.05 |
(a) Why is this a legitimate assignment of probabilities to outcomes?
all probabilities are greater than 0 and they sum to 1 all probabilities are greater than or equal to 0 they sum to 1 all probabilities are greater than or equal to 0 and they sum to 1
(b) What is the probability that the tasters agree when rating a
wine?
(c) What is the probability that Taster 1 rates a wine higher than
3?
What is the probability that Taster 2 rates a wine higher than
3?
(a)
Correct option:
all probabilities are greater than or equal to 0 they sum to 1.
(b)
The probability that the tasters agree when rating a wine is
(c)
Following table shows the row total and column total:
Taster 2 | ||||||
Taster 1 | 1 | 2 | 3 | 4 | 5 | Total |
1 | 0.03 | 0.02 | 0.01 | 0 | 0 | 0.06 |
2 | 0.02 | 0.09 | 0.05 | 0.02 | 0 | 0.18 |
3 | 0.01 | 0.05 | 0.29 | 0.05 | 0.01 | 0.41 |
4 | 0 | 0.02 | 0.05 | 0.2 | 0.01 | 0.28 |
5 | 0 | 0 | 0.01 | 0.01 | 0.05 | 0.07 |
Total | 0.06 | 0.18 | 0.41 | 0.28 | 0.07 | 1 |
So,
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