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Suppose a shipment of 180 electronic components contains 3 defective components. To determine whether the shipment...

Suppose a shipment of 180 electronic components contains 3 defective components. To determine whether the shipment should be​ accepted, a​ quality-control engineer randomly selects 3 of the components and tests them. If 1 or more of the components is​ defective, the shipment is rejected. What is the probability that the shipment is​ rejected?

Math   Statistics-And-Probability   
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Answer #1

Since out of 180 components 3 are defective then Probability of defective item will be 3/180= 0.0167

So if 3 are randomly selected , n=3 then by binomial probability formula

So, here K=1 the P(K>/=1)=P(K=1)+P(K=2)+P(K=3)

Calculation by above stated formula

=0.0484+0.0008++0.000005

=0.0493

hence P(the shipment is​ rejected)=0.0493

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