A stock analyst wondered whether the mean rate of return of financial, energy, and utility stocks differed over the past 5 years. He obtained a simple random sample of eight companies from each of the three sectors and obtained the 5-year rates of return shown in the accompanying table (in percent).
Financial Energy Utilities
10.73 12.89 11.98
15.12 13.96 5.86
17.21 6.33 13.46
5.07 11.23 9.82
19.50 18.93 3.95
8.16 20.73 3.44
10.38 9.60 7.11
6.75 17.40 15.70
(a) State the null and alternative hypotheses. Choose the correct answer below.
B.
H0: μfinancial=μenergy=μutilities and H1: at least one of the means is different
Your answer is correct.
(b) Normal probability plots indicate that the sample data come from normal populations. Are the requirements to use the one-way ANOVA procedure satisfied?
C.
Yes, because there are k=3 simple random samples, one from each of k populations, the k samples are independent of each other, and the populations are normally distributed and have the same variance.
Your answer is correct.
(c) Are the mean rates of return different at the α=0.05 level of significance?
Use technology to find the F-test statistic for this data set.
F0equals=2.08
(Round to two decimal places as needed.)
Determine the P-value and state the appropriate conclusion below.
Since the P-value is
nothing ,
there
▼
is
is not
enough evidence to reject the null hypothesis. Thus, we
▼
can
cannot
conclude that the mean rates of return are different at the α=0.05 level of significance.
(Round to three decimal places as needed.)
excel data analysis tool for one factor anova,steps are: write
data>menu>data>data analysis>anova :one factor>enter
required labels>ok, and following o/p Is obtained,
Anova: Single Factor | ||||||
SUMMARY | ||||||
Groups | Count | Sum | Average | Variance | ||
financial | 8 | 92.92 | 11.615 | 26.64471 | ||
energy | 8 | 111.07 | 13.88375 | 24.02074 | ||
utilities | 8 | 71.32 | 8.92 | 20.59 | ||
ANOVA | ||||||
Source of Variation | SS | df | MS | F | P-value | F crit |
Between Groups | 99.00 | 2 | 49.5009 | 2.0841 | 0.149 | 5.78 |
Within Groups | 498.78 | 21 | 23.752 | |||
Total | 597.78 | 23 |
F stat = 2.08
p value=0.149
Since the P-value is 0.149 ,
there is not
enough evidence to reject the null hypothesis. Thus, we
▼
cannot
conclude that the mean rates of return are different at the α=0.05 level of significance.
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