A doctor wants to estimate the HDL cholesterol of all 20- to 29-year-old females. How many subjects are needed to estimate the HDL cholesterol within 4 points with 99 % confidence assuming sigma equals 12.7 question mark Suppose the doctor would be content with 95 % confidence. How does the decrease in confidence affect the sample size required?
99% and 95%
At 99% confidence interval the critical value is z0.005 = 2.58
Margin of error = 4
Or, z0.005 * = 4
Or, 2.58 * 12.7/ = 4
Or, n = (2.58 * 12.7/4)^2
Or, n = 68
At 95% confidence interval the critical value is z0.025 = 1.96
Margin of error = 4
Or, z0.025 * = 4
Or, 1.96 * 12.7/ = 4
Or, n = (1.96 * 12.7/4)^2
Or, n = 39
Since the confidence level decreases, the required of sample size also drcreases.
Get Answers For Free
Most questions answered within 1 hours.