It is very common for television series to draw a large audience for special events of for cliff-hanging story lines. Suppose that on one of these occasions, the special show drew viewers from 42% of all US TV households. Suppose that three TV households are randomly selected. What is the probability that none of the three households viewed this special show?
Let , X be the number of households viewed special show.
P = 0.42 , n = 3
X follows Binomial distribution with n = 3 and p = 0..42
We have to find probability that none of the three households viewed this special show.
In notation we have to find P( x = 0 )
Formula for Binomial distribution ,
,
The probability that none of the three households viewed this special show is 0.1951
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