Question

It is very common for television series to draw a large audience for special events of for cliff-hanging story lines. Suppose that on one of these occasions, the special show drew viewers from 42% of all US TV households. Suppose that three TV households are randomly selected. What is the probability that none of the three households viewed this special show?

Answer #1

Let , X be the number of households viewed special show.

P = 0.42 , n = 3

X follows Binomial distribution with n = 3 and p = 0..42

We have to find probability that none of the three households viewed this special show.

In notation we have to find P( x = 0 )

Formula for Binomial distribution ,

,

*The probability that none of the three households
viewed this special show is 0.1951*

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Nielsen ratings are very important to both advertisers and
television programmers because the cost of television advertising
time is based on these ratings. A show’s rating is the
number of households in Nielsen’s sample that are tuned to that
show divided by the number of television-owning households—120.6
million in the United States. One rating point represents 1 percent
of the households (HHS) in the TV market. Nielsen’s TV ratings are
referred to as C3 and measure viewers who watch commercials...

Delta airlines case study
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