While conducting a oneway ANOVA comparing 6 treatments with 10 observations per treatment, computed value for SST = 290 and MSE = 5. Find the value of F and also construct the ANOVA table.
There are 60 observations. N = 60 and k = 6 treatments
Source of variation 
SS(Sum of square) 
Df 
MS(Mean Square) 
F 
Treatment 
SST = 290 
k 1 = 5 
MST = 58 
11.6 
Error 
SSE = 270 
nk = 54 
MSE = 5 

Total 
TSS = 560 
n1 = 59 
Here number of treatments k = 6
Total number of observations N = 60
The degrees of freedom for total = N1 = 60 – 1 = 59
The degrees of freedom for treatments = k1 = 6 – 1 = 5
The degrees of freedom for Error = N – k = 54
MSE = 5
MSE = SSE / N – K
SSE = 5*54 = 270
SST = 290
MST = SST / k1 = 290/5 = 58
SS(Total) = SST + SSE
TSS = 290 + 270 = 560
F = MST /MSE = 58 / 5 = 11.6
F = 11.6
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