One group of accounting students took a distance learning class, while another group took the same course in a traditional classroom. At α = .10, is there a significant difference in the mean scores listed below?
Statistic | Distance | Classroom | ||
Mean scores | x⎯⎯1x¯1 | = 9.7 | x⎯⎯2x¯2 | = 10.9 |
Sample std. dev. | s1 | = 2.7 | s2 | = 2.5 |
Number of students | n1 | = 21 | n2 | = 21 |
(a) consider following hypotheses. Assume
μ1 is the mean score of distance learning and
μ2 is the mean score of classroom
learning.
b. H0: μ1 –
μ2 = 0 vs. H1:
μ1 – μ2 ≠ 0
(b) Specify the decision rule. (Round your
answers to 3 decimal places. A negative value should be indicated
by a minus sign.)
Reject the null hypothesis if tcalc
< or tcalc
> .
(c) Find the test statistic
tcalc. (Round your answer to 4 decimal
places. A negative value should be indicated by a minus
sign.)
tcalc
(e-1) Use Excel to find the p-value.
(Round your answer to 3 decimal places.)
p-value
Two tailed test
Degrees of Freedom:
Critical value:
…………………..….using t table
Reject the Null Hypothesis, If tcal < -1.685 or tcal > 1.685
C)
Test statistic:
Conclusion:
So, Here Test statistic is lies in the Acceptance region, i.e. -1.685 < -1.4945 < 1.685, That is Fail to Reject Ho at 10% level of significance.
Using P-value Method:
P-value = 0.143 ..............Using t table
P-value > 0.10, That is Fail to Reject Ho at 10% level of significance.
Therefore, there is No Significant difference in the mean score listed.
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ta/2,df = t0.10/2,39 +1.685
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