A population is estimated to have a standard deviation of 6. We want to estimate the mean within 1, with a 99% level of confidence.
How large is a sample required? (Round your answer to the next whole number)
Solution :
Given that,
standard deviation = = 6
margin of error = E = 1
At 99% confidence level the z is ,
= 1 - 99% = 1 - 0.99 = 0.01
/ 2 = 0.01 / 2 = 0.005
Z/2 = Z0.005 = 2.576
Sample size = n = ((Z/2 * ) / E)2
= ((2.576 * 6) / 1)2
= 238.88 = 239
Sample size = 239
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