Question

Instructions The expectation is that you will show how the answers were found and what they...

Instructions

The expectation is that you will show how the answers were found and what they mean.

From a survey that Alika conducted for her veterinary medicine class, she found that 365 households out of a total of 1000 households claimed to own at least one dog or cat. Alika constructed a 95% confidence interval in order to predict the population proportion, π, leading to 0.3352 ≤ π≤ 0.3948. (She used the Excel function CONFIDENCE.NORM.)

Alika concluded that:

1) It was Ok to use the sample proportion p = 365/1000 = 0.365 to construct this confidence interval;

2) The proportion of households in her whole state that would claim to own a dog or cat would be between 33.52% and 39.48%; and

3) She was glad that she had not chosen a larger sample because a sample greater than n = 1000 would have caused the confidence interval to become wider and less precise.

Homework Answers

Answer #1

Sample proportion p = 365 / 1000 = 0.365

a)

95% confidence interval for is

p - Z/2 * sqrt ( p ( 1 - p) / n) <= <= p + Z/2 * sqrt ( p ( 1 - p) / n)

0.365 - 1.96 * sqrt( 0.365 * 0.635 / 1000) <= <= 0.365 + 1.96 * sqrt( 0.365 * 0.635 / 1000)

0.3352 <= <= 0.3948

b)

We conclude that,

We are 95% confident that population proportion is between 33.52% and 39.48%.

That is,

The proportion of houshold in her whole state that would claim to own a dog or cat would be

between 32.52% and 39.48%

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