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8% of all Americans live in poverty. If 47 Americans are randomly selected, find the probability...

8% of all Americans live in poverty. If 47 Americans are randomly selected, find the probability that

  Exactly 2 of them live in poverty.  
b. At most 4 of them live in poverty.  
c. At least 1 of them live in poverty.  
d. Between 3 and 7 (including 3 and 7) of them live in poverty.

Math   Statistics-And-Probability   
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Answer #1

in a binomial distribution p (X=x)=

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