Question

A botanist wishes to estimate the typical number of seeds for a certain fruit. She samples 72 specimens and counts the number of seeds in each. Use her sample results (mean = 71.1, standard deviation = 14.2) to find the 98% confidence interval for the number of seeds for the species. Enter your answer as an open-interval (i.e., parentheses) accurate to 3 decimal places. 98% C.I. =

Answer 1

We have given that,          
          
Sample mean =71.1  
Sample standard deviation =14.2
Sample size =72  
Level of significance=1-0.98=0.02  
Degree of freedom =71  
          
t critical value is (by using t table)=   2.38
          
Confidence interval formula is   

=(67.117,75.083) ...................98% confidence interval.