Suppose that you are taking a course. There are two midterms and a final exam. Each midterm impacts 25% of the course grade while final exam impacts 50% of the grade. The first and second midterm scores follow a normal distribution with mean 84 points and the standard deviation of 9 points and mean 85 points and the standard deviation of 6. Assume that the final exam is also normally distributed with mean 87 and standard deviation of 6 points. Let W be the overall grade you get from this class.
here let x1,x2 and x3 are scores on three exams
therefore W =0.25x1+0.25x2+0.5x3
a)
distribution of W is normal with below parameter
mean =0.25*84+0.25*85+0.5*87=85.75
and std deviation =sqrt((0.25*9)2+(0.25*6)2+(0.5*6)2)=4.0389
b)
probability that a randomly chosen student gets A from this class =P(X>90)=P(Z>(90-85.75)/4.0389)=P(Z>1.05)
=0.1469
c) probability that a randomly chosen person’s grade is at within approximately 4points of the general class average
=P(-4/4.0389<Z<4/4.0389)=P(-0.99<Z<0.99)=0.8389-0.1611 =0.6778
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