Question

A leading magazine (like Barron's) reported at one time that the average number of weeks an individual is unemployed is 32 weeks. Assume that for the population of all unemployed individuals the population mean length of unemployment is 32 weeks and that the population standard deviation is 4 weeks. Suppose you would like to select a random sample of 51 unemployed individuals for a follow-up study.

Find the probability that a single randomly selected value is greater than 31.3. P(X > 31.3) = (Enter your answers as numbers accurate to 4 decimal places.)

Find the probability that a sample of size n = 51 is randomly selected with a mean greater than 31.3. P( ¯ x > 31.3) =

Answer 1

SolutionA:

mean=32

sd=4

n=1

sample sd=pop sd/sqrt(n)=4/sqrt(1)=4/1=4

P(X>31.3)

enter below R code:

pnormGC(bound=31.3,region="above", mean=32,sd=4,graph=TRUE)

0.5694602

ANSWER:

0.5695

SolutionB:

mean=32

sd=4

n=51

sample sd=pop sd/sqrt(n)=4/sqrt(51)=0.560112

enter below R code

pnormGC(bound=31.3,region="above", mean=32,sd=4,graph=TRUE)

0.8943046

ANSWER:0.8943