Question

An intergovernmental organization surveyed 1250 homes at random in each of its member countries in​ 2011, and found that the number of rooms per person in homes from Country A was 2.7 on​ average, whereas in Country B it was 2.4. Assume that the standard deviation is​ 35% of these average values. Do homes in Country A in general have more rooms per person than homes in Country​ B? Complete parts​ a) through​ d) below.

A what is the test statistic? knowing the follwing:

H0 : u1-u2 = 0

HA : U1-u2 >0

B) what is the p-value?

Answer 1

Answer:

Given,

X1bar = 2.7

X2bar = 2.4

n = 1250

s1 = 0.35*2.7

= 0.945

s2 = 0.35*2.4

= 0.84

a)

Null hypothesis

Ho : 1 - 2 = 0

Alternative hypothesis

H1 : 1 - 2 > 0

b)

To give p value

test statistic = (x1bar - x2bar) / sqrt(s1^2/n1 + s2^2/n2)

substitute values

= (2.7 - 2.4) / sqrt(0.945^2/1250 + 0.84^2/1250)

= 0.3/0.03576

z = 8.389

P value = 0