Two wine tasters rate each wine they taste on a scale of 1 to 5. From data on their ratings of a large number of wines, we obtain the following probabilities for both tasters' ratings of a randomly chosen wine.
Taster 2 | |||||
Taster 1 | 1 | 2 | 3 | 4 | 5 |
1 | 0.04 | 0.03 | 0.02 | 0.00 | 0.00 |
2 | 0.03 | 0.09 | 0.05 | 0.02 | 0.00 |
3 | 0.02 | 0.05 | 0.20 | 0.05 | 0.02 |
4 | 0.00 | 0.02 | 0.05 | 0.20 | 0.02 |
5 | 0.00 | 0.00 | 0.02 | 0.02 | 0.05 |
a. What is the probability that the tasters agree when rating a wine?
b. What is the probability that Taster 1 rates a wine higher than 3?
c. What is the probability that Taster 2 rates a wine higher
than 3?
Taster 2 | ||||||
Taster 1 | 1 | 2 | 3 | 4 | 5 | total |
1 | 0.04 | 0.03 | 0.02 | 0 | 0 | 0.09 |
2 | 0.03 | 0.09 | 0.05 | 0.02 | 0 | 0.19 |
3 | 0.02 | 0.05 | 0.2 | 0.05 | 0.02 | 0.34 |
4 | 0 | 0.02 | 0.05 | 0.2 | 0.02 | 0.29 |
5 | 0 | 0 | 0.02 | 0.02 | 0.05 | 0.09 |
total | 0.09 | 0.19 | 0.34 | 0.29 | 0.09 | 1 |
a)
probability that the tasters agree when rating a wine =P(X=1,Y=1)+P(X=2,Y=2)+P(X=3,Y=3)+P(X=4,Y=4)+P(X=5,Y=5)=0.58
b)
probability that Taster 1 rates a wine higher than 3 =0.29+0.09=0.38
c)
probability that Taster 2 rates a wine higher than 3 =0.29+0.09=0.38
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