Find the value of the standard normal random variable z, called z0 such that:
(a) P(z≤z0)=0.9589
z0=
(b) P(−z0≤z≤z0)=0.0602
z0=
(c) P(−z0≤z≤z0)=0.6274
z0=
(d) P(z≥z0)=0.2932
z0=
(e) P(−z0≤z≤0)=0.4373
z0=
(f) P(−1.38≤z≤z0)=0.8340
z0=
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