You are conducting a test of homogeneity for the claim that two different populations have the same proportions of the following two characteristics. Here is the sample data.
Category | Population #1 |
Population #2 |
---|---|---|
A | 10 | 43 |
B | 69 | 10 |
What is the chi-square test-statistic for this data?
χ2=
Data =
Category |
Population 1 |
Population 2 |
Totals |
A |
10 |
43 |
53 |
B |
69 |
10 |
79 |
Totals |
79 |
53 |
132 |
Expected =
Category |
Population 1 |
Population 2 |
Totals |
A |
(79/132)*53 =31.72 |
(53/132)*53 = 21.28 |
53.00 |
B |
(79/132)*79 = 47.28 |
(53/132)*79= 31.72 |
79.00 |
Totals |
79.00 |
53.00 |
132.00 |
χ2 = ∑(observed−expected)2 / expected
χ2 = (10 – 31.75)^2 / 31.75 + ( 69 - 47.28)^2 / 47.28 + (43-21.28)^2 / 21.28 + (10-31.72)^2 / 31.72
χ2 = 14.87 + 9.98 + 22.17 + 14.87
χ2 = 61.89
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