A dependent random sample from two normally distributed populations gives the results shown below. Complete parts a and b below.
n=19
d =28.7
sd=3.8
a. Find the 90% confidence interval for the difference between the means of the two populations.
The 90% confident interval is from a lower limit of _?_ to an upper limit of _?_.
b. Find the margin of error for a 90% confidence interval for the difference between the means of the two populations.
The margin of ME = ?
a)
sample size , n = 19
Level of Significance , α = 0.10
Degree of freedom, DF= n - 1 = 18
t-critical value = t α/2,df =
1.7341
std dev of difference , Sd =
3.8000
std error , SE = Sd / √n = 0.8718
margin of error, E = t*SE = 1.5117
mean of difference , D̅ = 28.7000
confidence interval is
Interval Lower Limit= D̅ - E =
27.1883
Interval Upper Limit= D̅ + E = 30.2117
The 90% confident interval is from a lower limit of 27.2 to an upper limit of 30.2
b)
.margin of error = 1.5 [ as calculated above]
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