Question

In a random sample of 512 hospital patients, 102 were readmitted within 30 days of discharge....

In a random sample of 512 hospital patients, 102 were readmitted within 30 days of discharge. A 95% confidence interval for the proportion of all hospital patients who are readmitted within 30 days of discharge is about

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

sample proportion = 102 / 512 = 0.199

95% confidence interval for p is

- Z * sqrt( ( 1 - ) / n) < p < + Z * sqrt( ( 1 - ) / n)

0.199 - 1.96 * sqrt( 0.199 * 0.801 / 512) < p < 0.199 + 1.96 * sqrt( 0.199 * 0.801 / 512)

0.164 < p < 0.234

95% CI is ( 0.164 , 0.234)

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Suppose a hospital gets simple random sample of 600 patients opinions on conditions at that hospital...
Suppose a hospital gets simple random sample of 600 patients opinions on conditions at that hospital and the proportion of those patients who say that doctors always communicated well is 0.79. What is the 95% confidence interval for the true proportion of patients of that hospital that say doctors always communicated well?
a random sample of 45 days taken at a large hospital shows that a mean of...
a random sample of 45 days taken at a large hospital shows that a mean of 37 patients were treated in the emergency room (ER) per day. The standard deviation of the population is 4. Find the 95% confidence interval of the mean number of ER patients treated each day at the hospital. Express your answers as decimals to the nearest hundredth , please show work and formulas used to solve this , thanks so much!
An administrator for a hospital wished to estimate the average number of days required for inpatient...
An administrator for a hospital wished to estimate the average number of days required for inpatient treatment of patients between the ages of 25 and 34. A random sample of 500 hospital patients between these ages produced a mean and standard deviation equal to 5.4 and 3.1 days, respectively. Assume that ages of patients are normally distributed. (a) Construct a 95% confidence interval for the mean length of stay for the population of patients from which the sample was drawn....
A hospital administrator sampled 100 records at random and found that a 95% confidence interval for...
A hospital administrator sampled 100 records at random and found that a 95% confidence interval for the proportion of all patients who developed a secondary infection during their hospital stay was between 0.43 and 0.63. Asked to explain the meaning of this interval, the administrator’s intern says, “We can say with confidence that 95% of patients are between 43% and 63% likely to develop secondary infections during their stay.” a. Is the intern right? Justify your answer with a sentence...
In a random sample of 30 arthroscopic surgeries, 12% were unsuccessful. Find a 95% confidence interval...
In a random sample of 30 arthroscopic surgeries, 12% were unsuccessful. Find a 95% confidence interval for the proportion of arthroscopic surgeries in the population that were unsuccessful.
In a random sample of 30 arthroscopic surgeries, 12% were unsuccessful. Find a 95% confidence interval...
In a random sample of 30 arthroscopic surgeries, 12% were unsuccessful. Find a 95% confidence interval for the proportion of arthroscopic surgeries in the population that were unsuccessful.
A hospital administrator wants to determine the proportion of emergency room patients that use the emergency...
A hospital administrator wants to determine the proportion of emergency room patients that use the emergency room (ER) for non-emergency care. She randomly samples records from 350 ER patients and determines that 74 of those patients required only non-emergency care. 1. The administrator constructs a 90% confidence interval for the true proportion of all ER patients who use the ER for non-emergency care. The error bound for the proportion EBP for this confidence interval is: A. 0.036 B. 0.072 C....
A random sample of 1200 Freshmen at UGA were asked if they had applied for student...
A random sample of 1200 Freshmen at UGA were asked if they had applied for student football tickets. The proportion who answered yes was 0.86. The standard error of this estimate is 0.010. (a) Find the margin of error for a 95% confidence interval for the population proportion who applied for football tickets. (3 decimal places) (b) Construct the 95% confidence interval. Lower Limit (3 decimal places) Upper Limit (3 decimal places) (c) Since the sample was randomly selected, will...
Two hundred patients who had symptoms were also tested. Of these patients,9 percent was infected with...
Two hundred patients who had symptoms were also tested. Of these patients,9 percent was infected with the virus. Find the 95% confidence interval for the percent of all paitents who have symptoms at that hospital and who are infected with the virus
Suppose a hospital would like to estimate the proportion of patients who feel that physicians who...
Suppose a hospital would like to estimate the proportion of patients who feel that physicians who care for them always communicated effectively when discussing their medical care. A pilot sample of 40 patients found that 18 reported that their physician communicated effectively. Determine the additional number of patients that need to be sampled to construct a 95​% confidence interval with a margin of error equal to 3​% to estimate this proportion.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT