Question

1.A fast-food chain claims that the fat content of one of its cheeseburgers is 22 grams....

1.A fast-food chain claims that the fat content of one of its cheeseburgers is 22 grams. A consumer health group wanted to check this claim, so it obtained a random sample of 20 cheeseburgers from the chain and measured the fat content. The fat contents (in grams) are shown below, rounded to the nearest gram.

Use Excel to test whether the mean fat content is different from 22 grams. Identify the p-value from the output, rounding to three decimal places.

23
21
21
21
21
23
24
23
22
22
22
22
25
22
24
23
24
24
23
23

2.

Which of the following answers give valid null and alternative hypotheses for a hypothesis test?

Select all correct answers.

Select all that apply:

  • H0:μ=15; Ha:μ≤15

  • H0:μ=15; Ha:μ<15

  • H0:μ=15; Ha:μ≠15

  • H0:μ≠15; Ha:μ=15

  • 3. A researcher claims that the incidence of a certain type of cancer is less than 5%. To test this claim, the a random sample of 4000 people are checked and 170 are determined to have the cancer.

    The following is the setup for this hypothesis test:

    {H0:p=0.05 Ha:p<0.05

  • Find the test statistic for this hypothesis test for a proportion. Round your answer to 2 decimal places.

Homework Answers

Answer #1

1 ) let us consider H0 :

H1 :

since the sample size is less than 30 so we will use t test in minitab for one samle

we have the following output

One-Sample T: cheesburgers

Test of μ = 22 vs ≠ 22


Variable N Mean StDev SE Mean T P
cheesburgers 20 22.650 1.182 0.264 2.46 0.024

the p value is 0.024

2 ) the correct hypothesis setups are

  • H0:μ=15; Ha:μ<15

  • H0:μ=15; Ha:μ≠15

3 )H0:p=0.05

Ha:p<0.05 ( left tailed )

using the minitab for 1 sample proportion we have the output

Test of p = 0.05 vs p < 0.05


Sample X N Sample p 95% Upper Bound Z-Value P-Value
1 170 4000 0.042500 0.047746 -2.18 0.015

test statistic is -2.18

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A fast food chain claims that the average fat content in one of their burgers is...
A fast food chain claims that the average fat content in one of their burgers is 270 grams. A consumer group test 15 samples and finds that the content is 330 grams with a standard deviation of 45 grams. Test the manufacturer’s claim at (a) L/S 0.05 HW 11-1 (b) L/S 0.01 HW 11-2 A fast food chain claims that the average fat content in one of their burgers is less than 270 grams. A consumer group test 15 samples...
A fast-food chain claims one small order of its tater tots weighs 90 grams. Ava thinks...
A fast-food chain claims one small order of its tater tots weighs 90 grams. Ava thinks she is getting less than what the restaurant advertises. She weighs the next 14 random orders of tater tots before she eats them and finds the sample mean is 89.3 grams and the standard deviation is 3.71 grams. What conclusion can be drawn at α = 0.05? There is not sufficient evidence to prove the fast-food chain advertisement is true. There is sufficient evidence...
A fast-food chain claims one large order of its fries weighs 170 grams. Joe thinks he...
A fast-food chain claims one large order of its fries weighs 170 grams. Joe thinks he is getting less than what the restaurant advertises. He weighs the next 12 random orders of fries before he eats them and finds the sample mean is 165.9 grams and the standard deviation is 11.98 grams. What conclusion can be drawn at α = 0.10? There is not sufficient evidence to prove the fast-food chain advertisement is true. There is sufficient evidence to prove...
1. A cereal company claims the mean sodium content in one serving of its cereal is...
1. A cereal company claims the mean sodium content in one serving of its cereal is 230 milligrams. You work for a national health service and are asked to test this claim. You find that a random sample of 50 servings has a mean sodium content of 234 milligrams and a standard deviation of 10 mg. At α = 0.01, do you have enough evidence to reject the company’s claim? Hypothesis: Test statistic: p-value: Conclusion: Interpretation:
From previous studies, it is concluded that 40% of workers indicate that they are mildly dissatisfied...
From previous studies, it is concluded that 40% of workers indicate that they are mildly dissatisfied with their job. A researcher claims that the proportion is smaller than 40% and decides to survey 400 working adults. Test the researcher's claim at the α=0.01 significance level. Preliminary: Is it safe to assume that n≤0.05 of all subjects in the population? No Yes Verify np(1−p)≥10. Round your answer to one decimal place. np(1−p)= Test the claim: The null and alternative hypotheses are...
The Fast N’ Hot food chain wants to test if their “Buy One, Get One Free”...
The Fast N’ Hot food chain wants to test if their “Buy One, Get One Free” program increases customer traffic enough to support the coast of the program. For each of 15 stores, one day is selected at random to record customer traffic with the program in effect and one day is selected at random to record customer traffic with program not in effect. The results of the experiment are documented in DATA. At x=0.05, test the hypothesis that the...
NBC claims that viewers spend a daily average of 98.8 minutes watching their content. An advertiser...
NBC claims that viewers spend a daily average of 98.8 minutes watching their content. An advertiser wants to verify this and conducts a poll of 33 random viewers who claim to watch NBC. The poll showed that this group spends a daily average of 88.9 minutes watching NBC with a standard deviation of 20.7 minutes. Use a 0.005 significance level to test the claim that the daily average amount of time NBC viewers watch NBC is less than 98.8 minutes,...
13. The Fast N’ Hot food chain wants to test if their “Buy One, Get One...
13. The Fast N’ Hot food chain wants to test if their “Buy One, Get One Free” program increases customer traffic enough to support the cost of the program. For each of 15 stores, one day is selected at random to record customer traffic with the program in effect, and one day is selected at random to record customer traffic with program not in effect. The results of the experiment are documented in DATA link. For each store, compute difference...
The Fast N’ Hot food chain wants to test if their “Buy One, Get One Free”...
The Fast N’ Hot food chain wants to test if their “Buy One, Get One Free” program increases customer traffic enough to support the cost of the program. For each of 15 stores, one day is selected at random to record customer traffic with the program in effect, and one day is selected at random to record customer traffic with program not in effect. The results of the experiment are documented in DATA. For each store, compute difference = traffic...
A fitness trainer claims that high intensity power training decreases the body fat percentages of females....
A fitness trainer claims that high intensity power training decreases the body fat percentages of females. The table below shows the body fat percentages of eight females before and after 10 weeks of high intensity power training. At alphaαequals=0.10 is there enough evidence to support the​trainer's claim? Assume the samples are random and​ dependent, and the population is normally distributed. Complete parts​ (a) through​ (e) below. Female Body_Fat_%_(before) Body_Fat_%_(after) 1 27.2 27.1 2 23.6 23 3 23.9 23.8 4 23.5...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT