The following observations were obtained when conducting a two-way ANOVA experiment with no interaction
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Factor A | ||||||||||||||||||||||
Factor B | 1 | 2 | 3 | 4 | X⎯⎯⎯jX¯j for Factor B | |||||||||||||||||
1 | 5 | 2 | 2 | 1 | 2.500 | |||||||||||||||||
2 | 9 | 6 | 9 | 8 | 8.000 | |||||||||||||||||
3 | 15 | 11 | 13 | 16 | 13.750 | |||||||||||||||||
X−iX−i for Factor A | 9.667 | 6.000 | 8.000 | 8.333 | X⎯⎯⎯⎯⎯⎯=8.083X¯¯ = 8.083 | |||||||||||||||||
a. Calculate SST, SSA, SSB, and SSE. (Round intermediate calculations to at least 4 decimal places. Round your answers to 2 decimal places.)
b. Calculate MSA, MSB, and MSE. (Round intermediate calculations to at least 4 decimal places. Round your answers to 2 decimal places.)
c. Construct an ANOVA table. (Round intermediate calculations to at least 4 decimal places. Round "SS", "MS" to 2 decimal places, "F" 3 decimal places.)
d. At the 10% significance level, do the levels of Factor B differ?
Yes, since we reject the null hypothesis.
No , since we reject the null hypothesis.
Yes, since we do not reject the null hypothesis.
No, since we do not reject the null hypothesis.
e. At the 10% significance level, do the levels of Factor A differ?
Yes, since we reject the null hypothesis.
No, since we reject the null hypothesis.
Yes, since we do not reject the null hypothesis.
No, since we do not reject the null hypothesis.
Applying ANOVA"
Source of Variation | SS | df | MS | F | P-value |
factor B | 253.1667 | 2 | 126.5833 | 59.1818 | 0.0001 |
factor A | 16.9167 | 3 | 5.6389 | 2.6364 | 0.1442 |
Error | 12.8333 | 6 | 2.1389 | ||
Total | 282.9167 | 11 |
a)
SST=282.92
, SSA=16.92
SSB=253.17,
and SSE=12.83
b)
MSA=5.64
, MSB,=126.58
and MSE=2.14
c)
Source of Variation | SS | df | MS | F | P-value |
factor B | 253.17 | 2 | 126.58 | 59.182 | 0.0001 |
factor A | 16.92 | 3 | 5.64 | 2.636 | 0.1442 |
Error | 12.83 | 6 | 2.14 | ||
Total | 282.92 | 11 |
d) Yes, since we reject the null hypothesis.
e)
No, since we do not reject the null hypothesis.
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