There are two elementary schools in Caleb's community. Third graders in both schools recently took the same standardized exam. A random sample of 45 third graders from the first school has a mean score of 75. A random sample of 39 third graders from the second school has a mean score of 78. Assume the population standard deviations of the third graders' scores are known to be 10 for the first school and 5 for the second school. Construct and interpret a 95% confidence interval for the true difference between the mean exam scores for the two schools.
Solution:
point estimate = - = 75 - 78 = -3
c = 95% = 0.95
= 1 - c = 1 - 0.95 = 0.05
/2 = 0.025
= 2.576 ..(Using z table)
Margin of error =
=
= 3.3165
Confidence interval is
point estimate margin of error
-3 3.3165
(-3 - 3.3165, -3 + 3.3165)
(-6.3165 , 0.3165)
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