96 Diamonds found in an area 1120 square meters. The diamonds were scattered implying the area has a poisson distribution with mean 96/1120 = sites per squared meter, Under this assumption, if an area of 20 square metres are chosen:
A. List the possible values of X, number of diamonds in the chosen area of 20 square metres. What is the value of the parameter of the distribution of X in 20 square metres
From answer A find the probability in the 20 square metres of finding -
No diamonds
Exactly one diamond
More than one diamond
Number of diamonds found in 1120 square meters area = 96
Average number of diamond found in 1120 square meters area = 96 /1120.
Let X be number of diamond found in 20 square meters area.
m = Average number of diamond found in 20 square meters area = 20 * 96 / 1120 = 1.7143.
The probability distribution of random variable X is Poisson with parameter m = 1.7143.
The p.m.f. of X is
i) P ( no diamond found in 20 square meter area chosen) = P ( X= 0)
ii) P ( exactly one diamond found in 20 square meter area chosen) = P ( X=1)
iii) P ( more than one diamond found in 20 square meter area chosen) = P(X>1) = 1 - P(X<=1)
= 1- P(X=0) - P(X=1)
= 1 - 0.1801 - 0.3087
= 0.5112
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