Test the hypothesis using the p-value approach
Upper H 0H0: pequals=0.3
versus
Upper H 1H1: pgreater than>0.3
n=200; x=65, alphaαequals=0.01
Is np 0 left parenthesis 1 minus p 0 right parenthesisnp01−p0greater than or equals≥10? yes or no
p value (round to three decimal places)=
(reject or do not reject?) the null hypothesis because the p value is (greater or less) than x.
Here we have n = 200, x = 65, so
The hypothesis are
H0: P = 0.3 v/s H1 : P > 0.3
Here np = 200 * 0.33 = 66 , nq = 200 * 0.67 = 134
Here both np and nq both are greater than or equal to 10.
The test statistic is
= 0.93
Here test is right tailed. So the p value is given by
p ( z > 0.93 ) = 1 - p ( z 0.93 )
Look in to te probability section of stnadard normal probability table for z value 0.9 and 0.03 . We get probability as 0.8238.
p ( z > 0.93 ) = 1 - 0.8238 = 0.176
Here p value > (0.01 ) . Hence we failed to reject null hypothesis.
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