A professor records the time (in minutes) that it takes 16 students to complete an exam. Compute the SS, the variance, and the standard deviation assuming the 16 students constitute a population and assuming the 16 students constitute a sample. (Round your answers for variance and standard deviation to two decimal places.) 53 39 23 24 32 22 38 47 43 20 44 42 13 31 32 37 (a) the 16 students constitute a population SS Incorrect: Your answer is incorrect. variance Incorrect: Your answer is incorrect. standard deviation Incorrect: Your answer is incorrect. min (b) the 16 students constitute a sample SS variance standard deviation min
Ans:
xi | (xi-33.75)^2 | |
1 | 53 | 370.5625 |
2 | 39 | 27.5625 |
3 | 23 | 115.5625 |
4 | 24 | 95.0625 |
5 | 32 | 3.0625 |
6 | 22 | 138.0625 |
7 | 38 | 18.0625 |
8 | 47 | 175.5625 |
9 | 43 | 85.5625 |
10 | 20 | 189.0625 |
11 | 44 | 105.0625 |
12 | 42 | 68.0625 |
13 | 13 | 430.5625 |
14 | 31 | 7.5625 |
15 | 32 | 3.0625 |
16 | 37 | 10.5625 |
Total | 540 | 1843 |
mean | 33.75 |
a)
SS=1843
population variance=1843/16=115.1875
population standard deviation=sqrt(115.1875)=10.7325
b)
SS=1843
sample variance=1843/(16-1)=122.8667
sample standard deviation=sqrt(122.8667)=11.0845
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