Question

The First National Bank of Wilson has 680 checking account
customers. A recent sample of 60 of these customers showed 21 have
a Visa card with the bank.

Construct the 90% confidence interval for the proportion of
checking account customers who have a Visa card with the bank. (Use
*z* Distribution Table.) **(Round your answers to 3
decimal places.)**

Answer #1

sample success x= | 21 | |||

sample size n= | 60 | |||

sample proportion p̂ =x/n= | 0.3500 | |||

population size N= | 680 | |||

std error Se =(√(p*(1-p)/n))*(√((N-n)/(N-1))= | 0.0588 | |||

for 90 % CI value of z= | 1.645 | |||

margin of error E=z*std error = | 0.097 | |||

lower confidence bound=p̂-E= | 0.253 | |||

upper confidence bound=p̂+E= | 0.447 |

0% confidence interval for the proportion **=(0.253 ,
0.447)**

The First National
Bank of Wilson has 680 checking account customers. A recent sample
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bank.
Construct the 90% confidence interval for the proportion of
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decimal places.)

The First National Bank of Wilson has 660 checking account
customers. A recent sample of 60 of these customers showed 35 have
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and

The First National Bank of Wilson has 720 checking account
customers. A recent sample of 60 of these customers showed 22 have
a Visa card with the bank.
Construct the 98% confidence interval for the proportion of
checking account customers who have a Visa card with the bank. (Use
z Distribution Table.) (Round your answers to 3 decimal
places.)
Confidence interval for the proportion is between and
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customers. A recent sample of 60 of these customers showed 35 have
a Visa card with the bank? Construct the 90% confidence interval
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card with the bank. (Use z Distribution Table.) (Round your answers
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Construct the 99% confidence interval for the proportion of
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