An article reported that some company was sued in Texas for sex discrimination over a minimum height requirement of 5 ft 5 in. The suit claimed that this restriction eliminated more than 94% of adult females from consideration. Let x represent the height of a randomly selected adult woman. Suppose that x is approximately normally distributed with mean 64 in. (5 ft 4 in.) and standard deviation 2 in.
(b) What proportion of adult women would be excluded from employment as a result of the height restriction? (Round the answer to one decimal place.)
µ = 64
sd = 2
b) minimum height requirement = 5ft 5 in = 5 * 12 + 5 = 65 in
= P(Z < 0.5)
= 0.6915
= 69.2% or 0.7 (ans)
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