A new community safety education and outreach intervention is introduced in Biostats-ville, designed to lower the number of motor vehicle accidents occurring in that community. After 8 years of implementation, the average number of reported motor vehicle accidents per month (n=96) is recorded to be 85. Researchers know the general population average number of motor vehicle accidents per month from all communities of a similar size is 87 with a standard deviation of 8.5.
Use the data above examining the research question of interest: "Does Biostats-ville (with the new community safety education and outreach intervention) have a different average number of reported motor vehicle accidents per month than the population average of communities of a similar size?"
What is the p-value associated with your test statistic? (rounded to the nearest ten thousandth)
*Hint: remember what type of test you are conducting (one-tailed vs. two-tailed).
0.0231 |
0.1291 |
0.3401 |
0.0214 |
0.3475 |
Solution:
Here, we have to use one sample z test for population mean.
Null hypothesis: H0: Biostats-ville (with the new community safety education and outreach intervention) has a same average number of reported motor vehicle accidents per month than the population average of communities of a similar size.
Alternative hypothesis: Ha: Biostats-ville (with the new community safety education and outreach intervention) has a different average number of reported motor vehicle accidents per month than the population average of communities of a similar size.
H0: µ = 87 vs. Ha: µ ? 87
This is a two tailed test.
We are given
Sample size = n = 96
Sample mean = Xbar = 85
Population standard deviation = ? = 8.5
Test statistic is given as below:
Z = (Xbar - µ) / [?/sqrt(n)]
Z = (85 – 87) / [8.5/sqrt(96)]
Z = -2/ 0.867528
Z = -2.3054
P-value = 0.0214
(By using z-table)
Required Answer: 0.0214
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