Test the null hypothesis H0:p=0.5against the alternative hypothesis HA:p<0.5, when 92 individuals in a random sample of 219 have a characteristic of interest.
Proportions are very sensitive to round-off error. Please ensure that you attempt to round p^as little as possible.
a) Calculate the value of the z test statistic, for testing the null hypothesis that the population proportion is 0.5.
Round your response to at least 3 decimal places.
b) The p-value falls within which one of the following ranges:
p-value > 0.50 | ||
0.10 < p-value < 0.50 | ||
0.05 < p-value < 0.10 | ||
p-value < 0.05 |
c) What conclusion can be made, at the 5% level of significance?
There is insufficient evidence to reject the null hypothesis, and therefore no significant evidence that the population proportion is not 0.5. | ||
There is sufficient evidence to reject the null hypothesis, in favour of the alternative that the population proportion is less than 0.5. |
Solution:
Part a
Test statistic formula for this test is given as below:
Z = (p̂ - p)/sqrt(pq/n)
Where, p̂ = Sample proportion, p is population proportion, q = 1 - p, and n is sample size
x = number of items of interest = 92
n = sample size = 219
p̂ = x/n = 92/219 = 0.420091324
p = 0.5
q = 1 - p = 0.5
Z = (p̂ - p)/sqrt(pq/n)
Z = (0.420091324 – 0.5)/sqrt(0.5*0.5/219)
Z = -2.3651
Test statistic = Z = -2.365
Part b
P-value = 0.0090
(by using z-table)
p-value < 0.05
Part c
P-value < 0.05
So, we reject the null hypothesis at 5% level of significance
Conclusion:
There is sufficient evidence to reject the null hypothesis, in favour of the alternative that the population proportion is less than 0.5.
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