Question

In a recent poll, 240 people were asked if they liked dogs, and 33% said they did. Find the margin of error of this poll, at the 95% confidence level.

Answer #1

Solution :

Given that,

n = 240

= 33% = 0.33

1 - = 1 - 0.33 = 0.67

At 95% confidence level the z is ,

= 1 - 95% = 1 - 0.95 = 0.05

/ 2 = 0.05 / 2 = 0.025

Z_{/2}
= Z_{0.025} = 1.96

Margin of error = E = Z_{ / 2} * (( * (1 - )) / n)

= 1.96 * (((0.33 * 0.67) / 240)

= 0.059

Margin of error = 0.059

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