Question

The CRS scores for Express entry applicants follow approximately the N(503,121) distribution. How high must the...

The CRS scores for Express entry applicants follow approximately the N(503,121) distribution.

How high must the score be, to be placed in the top 12% of all applicants.

Homework Answers

Answer #1

Solution :

Given that,  

mean = = 503

standard deviation = = 121

X N (503 , 121)

Using standard normal table ,

P(Z > z) = 12%

1 - P(Z < z) = 0.12

P(Z < z) = 1 - 0.12

P(Z < 1.18) = 0.88

z = 1.18

Using z-score formula,

x = z * +

x = 1.18 * 121 + 503 = 645.78

high must the score be 645.78

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