Question 1
TABLE 13- 2 A candy bar manufacturer is interested in trying to estimate how sales are influenced by the price of their product. To do this, the company randomly chooses 6 small cities and offers the candy bar at different prices. Using candy bar sales as the dependent variable, the company will conduct a simple linear regression on the data below: City Price ($) Sales River City 1.30 100 Hudson 1.60 90 Ellsworth 1.80 90 Prescott 2.00 40 Rock Elm 2.40 38 Stillwater 2.90 32
Referring to Table 13- 2, what percentage of the total variation in candy bar sales is explained by prices?
A) 48.19%
B) 78.39%
D) 88.54%
E) 100%
Question 2:
TABLE 13-2
A candy bar manufacturer is interested in trying to estimate how
sales are influenced by the price of their product. To do this, the
company randomly chooses 6 small cities and offers the candy bar at
different prices. Using candy bar sales as the dependent variable,
the company will conduct a simple linear regression on the data
below:
City | Price ($) | Sales |
River City | 1.30 | 100 |
Hudson | 1.60 | 90 |
Ellsworth | 1.80 | 90 |
Prescott | 2.00 | 40 |
Rock Elm | 2.40 | 38 |
Stillwater | 2.90 | 32 |
Referring to Table 13-2, to test whether a change in price will
have any impact on sales, what would be the critical values? Use
α = 0.05.
±3.1634 |
||
±2.5706 |
||
±2.7765 (choose this, this is the correct answer) |
||
±3.4954 |
Question 3:
TABLE 13- 2
A candy bar manufacturer is interested in trying to estimate how
sales are influenced by the price of their product. To do this, the
company randomly chooses 6 small cities and offers the candy bar at
different prices. Using candy bar sales as the dependent variable,
the company will conduct a simple linear regression on the data
below:
City | Price ($) | Sales |
River City | 1.30 | 100 |
Hudson | 1.60 | 90 |
Ellsworth | 1.80 | 90 |
Prescott | 2.00 | 40 |
Rock Elm | 2.40 | 38 |
Stillwater | 2.90 | 32 |
Referring to Table 13- 2, if the price of the candy bar is set at
$2, the predicted sales will be
65. |
||
30. |
||
100. |
||
90. |
Question 4
QUESTION 10
Broker | Clients | Sales |
1 | 27 | 52 |
2 | 11 | 37 |
3 | 42 | 64 |
4 | 33 | 55 |
5 | 15 | 29 |
6 | 15 | 34 |
7 | 25 | 58 |
8 | 36 | 59 |
9 | 28 | 44 |
10 | 30 | 48 |
11 | 17 | 31 |
12 | 22 | 38 |
1.
X Values
∑ = 12
Mean = 2
∑(X - Mx)2 = SSx = 1.66
Y Values
∑ = 390
Mean = 65
∑(Y - My)2 = SSy = 4918
X and Y Combined
N = 6
∑(X - Mx)(Y - My) = -80
R Calculation
r = ∑((X - My)(Y - Mx)) /
√((SSx)(SSy))
r = -80 / √((1.66)(4918)) = -0.8854
So r^2=0.7839
Hence answer here is
B) 78.39%
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