Refrigerator manufacturers design their freezer units to maintain temperatures within a certain range. Suppose a major refrigerator manufacturer wants the temperature of a particular model to have a standard deviation equal to
4degreesĀ°F.
The company tested the freezer under normal operation conditions. The table to the right shows the freezer temperature readings in degrees Fahrenheit. What is test statistic? ?
3.6 6.2 -2 1.2 5 -5.5 5.6 -5.7 0.5 -6.1 -6.1 0.6 -0.8 -1 -5.9
data
3.6 6.2 -2 1.2 5 -5.5 5.6 -5.7 0.5 -6.1 -6.1 0.6 -0.8 -1 -5.9
sd = s =
4.47381
= (15 - 1)*4.47381^2/4^2
= 17.5131039266
df = n-1 = 14
chi-critical value
1) left = =CHISQ.INV(0.025,14) = 5.628
2) right = =CHISQ.INV(0.975,14) = 26.11895
since TS lies between critical values
we fail to reject the null hypothesis at 5 % lvel of signifiance
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