Question

Describe the sampling distribution of ModifyingAbove p with caret. Assume the size of the population is 30 comma 000. nequals600​, pequals0.119 Describe the shape of the sampling distribution of ModifyingAbove p with caret. Choose the correct answer below. A. The shape of the sampling distribution of ModifyingAbove p with caret is not normal because n less than or equals 0.05 Upper N and np left parenthesis 1 minus p right parenthesis less than 10. B. The shape of the sampling distribution of ModifyingAbove p with caret is not normal because n less than or equals 0.05 Upper N and np left parenthesis 1 minus p right parenthesis greater than or equals 10. C. The shape of the sampling distribution of ModifyingAbove p with caret is approximately normal because n less than or equals 0.05 Upper N and np left parenthesis 1 minus p right parenthesis greater than or equals 10. D. The shape of the sampling distribution of ModifyingAbove p with caret is approximately normal because n less than or equals 0.05 Upper N and np left parenthesis 1 minus p right parenthesis less than 10. Determine the mean of the sampling distribution of ModifyingAbove p with caret. mu Subscript ModifyingAbove p with caret Baseline equals nothing ​(Round to three decimal places as​ needed.) Determine the standard deviation of the sampling distribution of ModifyingAbove p with caret. sigma Subscript ModifyingAbove p with caret Baseline equals nothing ​(Round to three decimal places as​ needed.)

Answer 1

given that

n = 600

p = 0.119

N= 30000

condition (1) n must be less than or equal to 0.05N

and

np*(1-p) must be greater than or equal to 10

C. The shape of the sampling distribution of ModifyingAbove p with caret is approximately normal because n less than or equals 0.05 Upper N and np left parenthesis 1 minus p right parenthesis greater than or equals 10.

Mean = p = 0.119

standard deviation = sqrt[((1-p)*p)/n]

= sqrt[((1-0.119)*0.119)/600]

= sqrt(0.000174732)

= 0.013