Question

Given the measurements: 2.6, 2.62, 2.65, 2.58, 2.61, 2.62, 2.59, 2.59, 2.6, and 2.63

What is the average length and standard deviation of this series of measurements?

Answer 1

Mean = (sum of all data)/(number of data values)

= (2.6 + 2.62 +  2.65 +  2.58 +  2.61 +  2.62 +  2.59 +  2.59 +  2.6 + 2.63)/ 10

= 26.09/10

= 2.609

= 2.61 (rounded to 2 decimals)

and

standard deviation =

where xi are given data values and x bar is the mean(calculated above)

n is the sample size = 10

setting the values, we get