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Eighty percent of the population is right-handed. Use Excels to generate the binomial probability Distribution for...

Eighty percent of the population is right-handed. Use Excels to generate the binomial probability

Distribution for the number of right-handers you might find in 20 randomly chosen individuals and turn in this output. Then answer the following questions.

  1. What is the most likely number of right-handers that you might find in 20 randomly chosen individuals?
  2. What is the probability of getting at most 14 right-handers in 20 randomly chosen individuals?
  3. What is the probability of getting at least 15 right-handers in 20 randomly chosen individuals?
  4. What is the mean number of right-handers you would find in 20 randomly chosen individuals?
  5. What is the standard deviation of the right-handers you would find in 20 randomly chosen individuals?
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Homework Answers

Answer #1

Solution:

p=0.80

n=20

What is the probability of getting at most 14 right-handers in 20 randomly chosen individuals?

P(X<=14)

Excel formual

=BINOM.DIST(14;20;0.8;TRUE)

=0.195792

0.195792

What is the probability of getting at least 15 right-handers in 20 randomly chosen individuals?

P(X>=15)

=1-P(X<=14)

1-BINOM.DIST(14;20;0.8;TRUE)

=1-0.195792

=0.804208

0.804208

What is the mean number of right-handers you would find in 20 randomly chosen individuals?

Mean=np=20*0.80=16

What is the standard deviation of the right-handers you would find in 20 randomly chosen individuals?

standard deviation=sqrt(npq)]

=sqrt(20*0.80*0.20)

=1.788854

standard deviation=1.788854

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