Eighty percent of the population is right-handed. Use Excels to generate the binomial probability
Distribution for the number of right-handers you might find in 20 randomly chosen individuals and turn in this output. Then answer the following questions.
Solution:
p=0.80
n=20
What is the probability of getting at most 14 right-handers in 20 randomly chosen individuals?
P(X<=14)
Excel formual
=BINOM.DIST(14;20;0.8;TRUE)
=0.195792
0.195792
What is the probability of getting at least 15 right-handers in 20 randomly chosen individuals?
P(X>=15)
=1-P(X<=14)
1-BINOM.DIST(14;20;0.8;TRUE)
=1-0.195792
=0.804208
0.804208
What is the mean number of right-handers you would find in 20 randomly chosen individuals?
Mean=np=20*0.80=16
What is the standard deviation of the right-handers you would find in 20 randomly chosen individuals?
standard deviation=sqrt(npq)]
=sqrt(20*0.80*0.20)
=1.788854
standard deviation=1.788854
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