Question

You are the operations manager for an airline and you are considering a higher fare level for passengers in aisle seats. How many randomly selected air passengers must you​ survey? Assume that you want to be 99​% confident that the sample percentage is within 5.5 percentage points of the true population percentage. Complete parts​ (a) and​ (b) below. a. Assume that nothing is known about the percentage of passengers who prefer aisle seats. nequals nothing ​(Round up to the nearest​ integer.)

Answer 1

Solution :

(a)

Given that,

= 0.5

1 - = 1 - 0.5 = 0.5

margin of error = E = 5.5% = 0.055

At 99% confidence level the z is ,

= 1 - 99% = 1 - 0.99 = 0.01

/ 2 = 0.01 / 2 = 0.005

Z_/2 = Z_0.005 = 2.576

sample size = n = (Z _{/ 2} / E )² * * (1 - )

= (2.576 / 0.055)² * 0.5 * 0.5

= 548.4

sample size =  549

549 randomly selected air passengers must you​ survey .